Psikologi Belajar Muhibbin Syah Pdf Download !!EXCLUSIVE!!
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The other one is to be very clear in the question.
In the second case, I would:
Abstract
This essay analyzes the concept of customer satisfaction in view of J.D. Bernal’s theory of partial/total integration. The first part of the essay, argues that customers’ satisfaction must be based on a mutual perspective. The second part, aims to find how customers’ satisfaction can be an indicator for firms’ profitability and survival, and thereby it can be used as a tool to make better sales and marketing strategies.
Key words: customer satisfaction, partial/total integration, mutual perspectives, firms’ profitability and survival
Introduction
According to Davis and Kuzmanović (1995), there is a need for increasing research on the concept of customer satisfaction. In the development of this essay, I am trying to identify the relationship between customer satisfaction and firms’ profitability and survival and analyze which one is better than the other, and put forward my own views on how one is better than the other.
I. The relationship between customer satisfaction and firms’ profitability and survival
Customer satisfaction has been defined by Musen (1971) as “the degree of customer acceptance, retention, and loyalty to the seller.” It has been shown in the study of Musen (1971) that customer satisfaction also has an important influence on the firms’ profitability and survival. In this study, the concept of customer satisfaction is defined as “the amount of satisfaction that a customer had with the company’s output; an explanation of why the company was taken to and what the other things done on the products. This customer satisfaction can also be called the degree of attachment between customer and the company’s product.”
Customer satisfaction can be increased by providing more convenient services, good quality of products, using customer-oriented staff, providing customer-oriented facilities, using innovative products or services, and all of the above. However, in the study of Musen (1971), it was explained that customer satisfaction was not directly related to companies’ profitability and survival but that it is influenced by the firms’ competitive advantages. In other words, customer satisfaction is considered as the result of the competitive advantage of the firms.
In this section, I have identified the relationships between customer satisfaction and firms’ profitability and survival.
Customer satisfaction and the provision of the services
Customer satisfaction is one of the indicators that can be used to measure the quality and efficiency of the services. In this study, I have identified three possible dimensions that
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Finding difference in x and y direction of a vector
So I want to find the difference in the x and y direction of a vector for example: Vect1 = (2,4,3);
I want to do something like this:
vec.rotate(xDiff, yDiff);
The idea is that I can get the rotated version of the vector but what I want to do is to subtract the rotated vector from the original, so that I get a difference vector of x and y:
vec.rotate(xDiff, yDiff);
vec.subtract(vec);
Is this something that can be done in one line using some sort of function (which is faster)?
A:
Assuming your vector has float values, you can use a vector expression:
vec.x-vec.rotate(xDiff, yDiff).x
By writing the vector as two separate expressions, we are only evaluating the effect of the rotation on the x coordinate of the vector.
If your vector has integer values, you can use an expression such as:
vec.x*(1.0-cos(alpha*xDiff))+vec.y*(1.0-sin(alpha*xDiff))
Which can easily be expressed as an arc cosine function in one line, but with a possibly slower result. This can be written as
( (sin(alpha*xDiff)-yDiff)/sqrt(1-(cos(alpha*xDiff)^2-1)))/2
Note that in the case of integer values, the denominator 2 will have the same effect as the vector.subtract, but as someone mentioned in the comments, this is a bit of a trick to get around this. If you just want to find the difference in the X and Y components, you can multiply the result by 2.
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