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Accessing the elements of a list through indices in a loop
I have the following code:
a = [-12, 0, -2, -1]
t = [[0, 0, 0, 0], [-1, 0, 0, 0], [0, 0, 0, 0], [0, 0, 0, 0]]
I want to make a loop (or something like that) that says “check all the ‘0’s of a” to see if they are the same. If they are the same then it returns the position of the ‘0’s in the list.
>>> print a == t
True
>>> print t
[[0, 0, 0, 0], [0, 0, 0, 0], [0, 0, 0, 0], [0, 0, 0, 0]]
>>> what is being tried
print a[0] == t[0]
True
>>> what I want in a loop
for i in a:
if a[i] == t[i]:
#print the i position of t
What can I do to achieve this?
A:
You can use list comprehension:
lst = [0,1,2]
print [1,2,3] == [0,1,2] # True
>>> [lst[i]==lst[i] for i in lst]
[True, True, True, True]
//
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https://documenter.getpostman.com/view/21870633/UzXRQuwM
https://colab.research.google.com/drive/1vvrkdTFiemXAyWbsMX6A7OS8t8CkS2xm
https://ello.co/subnessposor/post/wpetva80fb2buyatoi-2qa
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